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Madonna and Macklemore rumored in a 'Same Love' performance at the Grammys

Madonna visits the Hard Candy Fitness Roma at Colosseo on August 21, 2013 in Rome, Italy.
(Photo by Ernesto Ruscio/Getty Images)

There may be a surprise Grammy performance involving Madonna and Macklemore & Ryan Lewis on Sunday night. According to MTV News on Jan. 25, there is a possibility that the gay icon may pair up with the hot hip-hop duo to perform what has become known as the gay rights anthem.

An onstage performance of "Same Love" would be inspiring considering Madonna has been one of the more outspoken celebrities supporting gay rights over the last couple decades. Sources have confirmed that both Madonna and the Grammy-nominated pair will hit the stage. It is only speculation that they will perform the song that is up for Song of the Year.

A victory for Macklemore & Ryan Lewis and "Same Love" would be monumental for the hip-hop genre, a genre not particularly known as being progressive in gay rights. A greater victory will be the message sent on one of the biggest stages and having someone like Madonna perform the hook would be the perfect symbolism of a gay icon who has spent her career dedicating her voice to support the gay community.

This wouldn't be the first time Macklemore & Ryan Lewis had a guest performer sing the hook to the track. During the 2013 VMA's, Jennifer Hudson performed the hook along with the Mary Lambert, the original singer in the groundbreaking song.

Macklemore & Ryan Lewis are up for seven Grammy Awards, including Album of the Year.

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